Решение на Първа задача от Тони Ризов
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Към профила на Тони Ризов
Резултати
- 5 точки от тестове
- 0 бонус точки
- 5 точки общо
- 14 успешни тест(а)
- 3 неуспешни тест(а)
Код
Лог от изпълнението
...........F..F.F
Failures:
1) Array#subarray_count(subarray) work with empty arrays
Failure/Error: [].subarray_count([1]).should be_zero
NoMethodError:
undefined method `zero?' for [0, 0]:Array
# /tmp/d20111025-2903-lk5xk9/spec.rb:59:in `block (2 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
2) Array#occurences_count returns a hash that defaults to 0 when the key is not present
Failure/Error: [].occurences_count[:something].should eq 0
expected 0
got nil
(compared using ==)
# /tmp/d20111025-2903-lk5xk9/spec.rb:74:in `block (2 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
3) Array#occurences_count returns a hash, that does not change when indexed with a non-occuring element
Failure/Error: hash['b'].should eq 0
expected 0
got nil
(compared using ==)
# /tmp/d20111025-2903-lk5xk9/spec.rb:84:in `block (2 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/homework/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
Finished in 0.02075 seconds
17 examples, 3 failures
Failed examples:
rspec /tmp/d20111025-2903-lk5xk9/spec.rb:58 # Array#subarray_count(subarray) work with empty arrays
rspec /tmp/d20111025-2903-lk5xk9/spec.rb:73 # Array#occurences_count returns a hash that defaults to 0 when the key is not present
rspec /tmp/d20111025-2903-lk5xk9/spec.rb:81 # Array#occurences_count returns a hash, that does not change when indexed with a non-occuring element
История (1 версия и 0 коментара)
Тони обнови решението на 23.10.2011 00:15 (преди около 13 години)